 | Robert Wallace - 1870 - 164 σελίδες
...of the partial divisor. Multiply the complete divisor by the last figure of the root thus obtained, subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. Double the whole root already found for a partial divisor, and... | |
 | Ezra S. Winslow - 1872 - 256 σελίδες
...and to the right of the divisor, as before ; multiply the divisor, as it now stands, by the figure last placed in the quotient, and subtract the product...from the dividend, and to the remainder bring down the next period for a dividend, as before. 5. Multiply the quotient (now consisting of 3 figures) by... | |
 | Shelton Palmer Sanford - 1872 - 404 σελίδες
...divisor, to form tlie TRUE DIVISOR. IV. Multiply the TRUE DIVISOR by the second figure of the root, subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. V. Double the root already found for a NEW TRIAL DIVISOE, 5625(75... | |
 | Horatio Nelson Robinson - 1874 - 340 σελίδες
...the right of the divisor. IV. Multiply the divisor thus completed by the last figure of the root ; subtract the product from the dividend; and to the remainder bring down the next period for a new diindend. V. Double the right-hand figure of the last complete divisor for... | |
 | Lorenzo Fairbanks - 1875 - 472 σελίδες
...the right of the divisor. IV. Multiply the divisor thus obtained by the digit of the root last found: subtract the product from the dividend, and to the remainder' bring down the next period for a new dividend. V. Double the part of the root already found, for a new divisor,... | |
 | Thomas Henderson - 1876 - 114 σελίδες
...30, and also the square of the last figure. Multiply the complete divisor by the last root figure, subtract the product from the dividend, and to the remainder bring down the next period, if any, or add three cyphers, for a new dividend. To the last complete divisor add... | |
 | Joseph Ray - 1877 - 350 σελίδες
...right of the trial divisor. Prie. 2П. 4. Multiply the complete divisor by the last figure of the root; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. 5. Double the whole root found, for a new trial divisor, and continue... | |
 | James Bates Thomson - 1878 - 322 σελίδες
...place the result in the quotient. II. Multiply the wl&U divisor by the term placed in the quotient ; subtract the product from the dividend, and to the remainder bring down as many terms of the dividend as the case may require. Repeat the operation till all the terms of the dividend arc... | |
 | Shelton Palmer Sanford - 1879 - 348 σελίδες
...to form• the complete divisor. III. Multiply the complete divisor by the second term of the root, subtract the product from the dividend, and to the remainder bring down as many terms as may be necessary for a new dividend. IV. Double the terms of the root already found for a NEW TKIAL... | |
 | Joseph Ray - 1880 - 420 σελίδες
...annexing the quotient to the root and to the divisor; then multiply the complete divisor by the quotient, subtract the product from the dividend, and to the remainder bring down the next period as before. 4. Double the root as before, place it on the left as a trial divisor, proceeding... | |
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Multiply the divisor, thus augmented, by the last figure of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. 
