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" If two triangles have two angles of the one equal to two angles of the other, each to each, and one side equal to one side, viz. "
Elements of Geometry, Conic Sections, and Plane Trigonometry - Σελίδα 30
των Elias Loomis - 1871 - 58 σελίδες
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Chambers's information for the people, ed. by W. and R. Chambers, Τόμος 2

Chambers W. and R., ltd - 1842 - 744 σελίδες
...proposition gives still further information on this useful subject. It shows that if two triangle* have two angles of the one equal to two angles of the other, each to each, and one side equal to one aide, namely, either the sides adjacent to the equal angles, or the sides opposite...

The Penny Cyclopædia of the Society for the Diffusion of Useful ..., Τόμος 22

1842 - 526 σελίδες
...course) alone are enough to determine its form : or, as Euclid would express it, two triangles which have two angles of the one equal to two angles of the other, each to each, have the third angles equal, and all the sides of one in the same proportion to the corresponding sides...

The Penny Cyclopædia of the Society for the Diffusion of Useful ..., Τόμος 22

1842 - 538 σελίδες
...course) alone are • enough to determine its form : or, as Euclid would express it, two triangles which have two angles of the one equal to two angles of the other, each to each, have the third angles equal, and all the sides of one in the same proportion to • the corresponding...

The Penny Cyclopaedia of the Society for the Diffussion of Useful ..., Τόμος 22

1842 - 524 σελίδες
...course) alone are enough to determine its form : or, as Euclid would express it, two triangles which have two angles of the one equal to two angles of the other, each to each, have the third angles equal, and all the sides of one in the same proportion to the corresponding sides...

Elements of geometry: consisting of the first four,and the sixth, books of ...

Euclides - 1842 - 316 σελίδες
...bisected by BD, and that the right angle BED is equal to the right angle BFD, the two triangles EBD, FBD have two angles of the one equal to two angles of the other, and the side BD, which is opposite to one of the equal angles in each, is common to both ; therefore...

Elements of Geometry: Containing the First Six Books of Euclid, with a ...

John Playfair - 1842 - 332 σελίδες
...by BD ; and because the right angle BED, is equal to the right angle BFD, the two triangles EBD, FBD have two angles of the one equal to two angles of the other ; and the side BD, which is opposite to one of the equal angles in each, is common to both ; therefore...

Euclid's Elements of geometry [book 1-6, 11,12] with explanatory notes ...

Euclides - 1845 - 546 σελίδες
...than the angle EDF. Wherefore, if two triangles, &c. QED PROPOSITION XXVI. THEOREM. If two triangles have two angles of the one equal to two angles of the other, each to each, and one side equal to one side, viz. either the sides adjacent to the equal angles in each, or the sides...

The First Six, and the Eleventh and Twelfth Books of Euclid's Elements: With ...

Euclid, James Thomson - 1845 - 382 σελίδες
...all equal. Hence (I. 6) CH is equal to HD, DK to KE, &c. Also, in the triangles CHD, DK_E, there are two angles of the one equal to two angles of the other, each to each, and (hyp.) the sides CD, DE are equal : therefore (I. 26) the sides CH, HD are equal to DK, KE, each to...

Key to System of practical mathematics. 2 pt. No.xvii

Scottish school-book assoc - 1845 - 278 σελίδες
...1), and the side BC is = the side BA, being sides of an equilateral triangle ; .-. the Д» CBD, ABE, have two angles of the one equal to two angles of the other, and a side lying between these equal angles also equal ; .-• these triangles are equal in every respect,...

Euclid in Paragraphs: The Elements of Euclid: Containing the First Six Books ...

Euclid - 1845 - 218 σελίδες
...and that the right angle B pct Comtr. BED is equal to the right angle BFD; the two triangles EBD, FBD have two angles of the one equal to two angles of the other ; and the side BD, which is opposite to one of the equal angles in each, is common to both ; therefore...




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