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" Examining the formation of the above coefficients, we observe, that each coefficient was found by multiplying the coefficient of the preceding... "
An Introduction to Algebra Upon the Inductive Method of Instruction - Σελίδα 222
των Warren Colburn - 1831 - 276 σελίδες
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School Algebra

John Marvin Colaw - 1903 - 444 σελίδες
...is 1 , the S3cond is equal to the binomial exponent; and the coefficient of any succeeding term is found by multiplying the coefficient of the preceding term by the exponent of a in that term, and dividing by 1 more than the exponent of 6. The student should carefully review...

Standard Algebra

William James Milne - 1908 - 476 σελίδες
...the xewnd term is the same as the index of the required power. 6. The coefficient of any term may be found by multiplying the coefficient of the preceding term by the exponent of a in that term, and dividing this product by the number of the term. Ï. All the terms are positive,...

Practical Elementary Algebra

Joseph Victor Collins - 1908 - 442 σελίδες
...&)»=«»- 5 a-'& + rcfo-1) a'-%2- «(nl)(n-2) 3 , c ' 1 1x2 1x2x3 Thus, to get any coefficient we multiply the coefficient of the preceding term by the exponent of the leading letter and divide by 1 more than the exponent of the other letter. Now, while we saw that this rule...

A Grammar School Algebra

Fletcher Durell, Edward Rutledge Robbins - 1909 - 296 σελίδες
...of the second term it is the index of the required power. In each succeeding term the coefficient is found by multiplying the coefficient of the preceding term by the exponent of a in that term, and dividing by the exponent of Ь increased by 1. IV. Signs of Terms. If the binomial...

Practical Algebra, 2d Course by Jos. V. Collins, Βιβλίο 2

Joseph Victor Collins - 1911 - 330 σελίδες
...the exponent of (a — A) ?'n the left member ; also that each succeeding coefficient can be obtained by multiplying the coefficient of the preceding term by the exponent of the leading letter a, and dividing the product by the exponent of the other letter increased by 1. \. Raise (a...

First Year Algebra

William James Milne - 1911 - 360 σελίδες
...the second term is the same as the index of the required power. 6. The coefficient of any term may be found by multiplying the coefficient of the preceding term by the exponent of à in that term, and dividing this product by the number of the term. 7. All the terms are positive,...

Durell's Algebra: Two Book Course. Book One, Βιβλίο 1

Fletcher Durell - 1914 - 458 σελίδες
...of the second term it is the index of the required power. In each succeeding term the coefficient is found by multiplying the coefficient of the preceding term by the exponent of « in that term, and dividing by the number of the preceding term. IV. Signs of terms. If the binomial...

Elementary Algebra

Herbert Ellsworth Slaught, Nels Johann Lennes - 1915 - 402 σελίδες
...of the second term is the same as the index of the power. The coefficient of each succeeding term is found by multiplying the coefficient of the preceding term by the exponent of the first letter in that term and dividing by the exponent of the second letter increased by one. * Articles...

Elementary Algebra

Herbert Ellsworth Slaught, Nels Johann Lennes - 1915 - 412 σελίδες
...of the second term is the same as the index of the power. The coefficient of each succeeding term is found by multiplying the coefficient of the preceding term by the exponent of the first letter in that term and dividing by the exponent of the second letter increased by one. •Articles...

Elementary Algebra: Second Year Course

Florian Cajori - 1916 - 236 σελίδες
...is 1 and increases by 1 in each succeeding term. III. The coefficient of any term after the first is found by multiplying the coefficient of the preceding term by the exponent of a in that term, and divided by one more than the exponent of b. IV. If the binomial is a + b, the signs...




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