Multiply the divisor, thus increased, by the last figure of the root; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. 5. Double the whole root already found for a new divisor, and continue the... Putnam's Arithmetic - Σελίδα 196των Rufus Putnam - 1849 - 264 σελίδεςΠλήρης προβολή - Σχετικά με αυτό το βιβλίο
| Charles Davies - 1852 - 344 σελίδες
...root and also annex it to the divisor. IV. Multiply the divisor thus increased, by the last figure of the root ; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. V. Double the whole root thus found, for a new trial... | |
| Benjamin Greenleaf - 1852 - 348 σελίδες
...divisor''s place, and the divisor will be completed. Multiply the complete divisor by the last term of the root; subtract the product from the dividend, and to the remainder connect the three next terms, and proceed as before. EXAMPLES. 1. Find the cube root of a 3 +3a2J-|-3a6... | |
| Joseph Ray - 1852 - 408 σελίδες
...and also on the right of the divisor. 4th. Multiply the divisor thus increased by the last figure of the root; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. 5th. Double the whole root already found for a new divisor,... | |
| Joseph Ray - 1848 - 250 σελίδες
...and also on the right of the divisor. 4th. Multiply the divisor thus increased, by the last figure of the root; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. 5th. Double the whole root already found, for a new... | |
| Daniel Leach - 1853 - 622 σελίδες
...divisor. Multiply the. complete divisor by the last figure, and subtract the product from the partial dividend, and to the remainder annex the next period for a new partial dividend. To the complete divisor add the last figure of the root for a new trial divisor.... | |
| Mathew Wilson - 1854 - 210 σελίδες
...root and to the divisor. 6. Multiply the divisor thus increased by the figure of the root h:st found, subtract the product from the dividend, and to the...remainder annex the next period for a new dividend. 6. To the last divisor add the last figure of the root for a new divisor, with which proceed as before... | |
| James Gray - 1854 - 120 σελίδες
...and annex it also to the divisor. 4. Multiply the divisor thus completed by the last figure placed in the root : subtract the product from the dividend, and to the remainder bring down the third period for a new dividend ; proceed in the same manner till all the periods are... | |
| Charles D. Lawrence - 1854 - 336 σελίδες
...figure in the root. and alao to the right of the trial divisor for a true divisor. Multiply the true divisor by the last figure in the root. subtract the product from the d,vidend, and to the remainder bring down the next period for a second dividend. V. Double the part... | |
| Dana Pond Colburn - 1855 - 396 σελίδες
...Multiply the true divisor by the last root figure, placing the product under the dividend. Eighth. Subtract the product from the dividend, and to the...remainder annex the next period for a new dividend. Ninth. Add the square of the last quotient figure to the last true divisor and the number standing... | |
| George Roberts Perkins - 1855 - 388 σελίδες
...the result will be the TRUE DIVISOR. Multiply the true divisor by this last figure of the root, and subtract the product from the dividend, and to the remainder annex the next period, fur a NEW DIVIDEND. IV. To the last TRUE DIVISOR add the last figure of tlte root ; the sum, with a... | |
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