 Multiply the divisor, thus increased, by the last figure of the root; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. 5. Double the whole root already found for a new divisor, and continue the...  Putnam's Arithmetic - Σελίδα 196των Rufus Putnam - 1849 - 264 σελίδεςΠλήρης προβολή - Σχετικά με αυτό το βιβλίο
 | Whitman Peck - 1868 - 304 σελίδες
...of the root, to the trial divisor, also the square of the last root figure. Multiply the completed divisor by the last figure in the root, subtract the product from the dividend and bring down the next period. Proceed thus, till the figures in the root are equal in number to the periods.... | |
 | John Fair Stoddard - 1888 - 480 σελίδες
...term of the 2d column for the TBUE DIVISOK. Multiply this divisor lij the last term of the root, and subtract the product from the dividend, and to the remainder annex the next period, for the SECOND DIVIDEND. 6. Proceed in like manner till all the periods have been used. NOTE.— 1. If... | |
 | John Fair Stoddard - 1868 - 428 σελίδες
...term of the 2d column for the TRUE orviSOE. Multiply this divisor by the last term of the root, and subtract the product from the dividend, and to the remainder annex the next period, for the SECOND DIVIDEND. 6. Proceed in like manner till all the periods have been used. NOTE. — 1. If... | |
 | Stoddard A. Felter - 1868 - 360 σελίδες
...the trial divisor, will form the complete dieisor. V. Multiply and subtract as in simple division, and, to the remainder, annex the next period for a new dividend. VI. Proceed in the same way, until all the periods are brouglit down. NOTES. — 1-. If the dividend... | |
 | John Homer French - 1869 - 350 σελίδες
...square of the ones, for a complete divisor. 3. Multiply the complete divisor by the last figure of the root ; subtract the product from the dividend...remainder annex the next period for a new dividend. NOTES. — 1. If any dividend is less than the divisor, annex a cipher to the root; two- ciphers to... | |
 | Robert Stewart (of Dundee.) - 1871 - 248 σελίδες
...the sum of these three numbers is the complete divisor, which multiply by the last quotient figure ; subtract the product from the dividend, and to the...remainder annex the next period for a new dividend, to which find a divisor as before, and proceed in the same manner till all the periods are exhausted.... | |
 | Joseph Ray - 1866 - 420 σελίδες
...and also on the right of the divifor. 4th. Multiply the divisor thus increased by the last figure of the root; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. 5th. Double the whole root already found for a new divisor,... | |
 | Henry Beadman Bryant, Emerson Elbridge White, Corydon Giles Stowell - 1872 - 576 σελίδες
...trial divisor; the sum will be the true divisor. Multiply the true divisor by the last root figure, subtract the product from the dividend, and to the...remainder annex the next period for a new dividend. 5. Add twice the root figure last found to the last term in column 1st ; then add the square of the... | |
 | Shelton Palmer Sanford - 1872 - 404 σελίδες
...the trial divisor, to form tlie TRUE DIVISOR. IV. Multiply the TRUE DIVISOR by the second figure of the root, subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. V. Double the root already found for a NEW TRIAL DIVISOE,... | |
 | Philotus Dean - 1874 - 472 σελίδες
...divisor. Multiply this completed divisor by this last root figure; subtract the product, if possible, from the dividend, and to the remainder annex the next period for a new dividend. Double the whole root found, for a new trial divisor, and proceed as before, till all the periods have... | |
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