 | Horatio Nelson Robinson - 1860 - 470 σελίδες
...14. The three straight lines which bisect the three angles of a triangle, meet in the same point. 15. The two triangles, formed by drawing straight lines from any point within a parallelogram to the extremi ties of two opposite sides, are, together, one half the parallelogram. 16. The figure formed... | |
 | Horatio Nelson Robinson - 1865 - 474 σελίδες
...14. The three straight lines which bisect the three angles of a triangle, meet in the same point. 15. The two triangles, formed by drawing straight lines...extremities of two opposite sides, are, together, one half the parallelogram. 16. The figure formed by joining the points of bisection of the sides of... | |
 | Horatio Nelson Robinson - 1868 - 276 σελίδες
...14. The three straight lines which bisect the three angles of a triangle, meet in the same point. 15. The two triangles, formed by drawing straight lines...extremities of two opposite sides, are, together, one half the parallelogram. 16. The figure formed by joining the points of bisection of the sides of... | |
 | Aristophanes - 1868 - 216 σελίδες
...does not lie, the difference of the triangles thus formed is equal to half the parallelogram. Ex. 2. The two triangles, formed by drawing straight lines...point within a parallelogram to the extremities of ita opposite sides, are together half of the parallelogram. [J. HAMBLIN SMITH'S GEOMETRY— See Page... | |
 | Aristophanes - 1870 - 264 σελίδες
...of the triangles thus formed is equal to half the parallelogram. Ex. 2. The two triangles, fonr.ad by drawing straight lines from any point within a parallelogram to the extremities of its opposite sides, are together half of the parallelogram. [J. HAMBLIN SMITH'S GEOMETRY— See Page... | |
 | Euclides - 1871 - 136 σελίδες
...does not lie, the difference of the triangles thus formed is equal to half the parallelogram. Ex. 2. The two triangles, formed by drawing straight lines...point within a parallelogram to the extremities of its opposite sides, are together half of the parallelogram. 5—2 To describe a parallelogram that... | |
 | Euclides, James Hamblin Smith - 1872 - 376 σελίδες
...does not lie, the difference of the triangles thus formed is equal to half the parallelogram. Ex 2. The two triangles, formed by drawing straight lines...point within a parallelogram to the extremities of its opposite sides, are together half of the parallelogram. PROPOSITION XLII. PROBLEM. To describe... | |
 | Jacques Claude Demogeot - 1874 - 408 σελίδες
...does not lie, the difference of the triangles thus formed is equal to half the parallelogram. Ex. 2. The two triangles, formed by drawing straight lines...point within a parallelogram to the extremities of its opposite sides, are together half of the parallelogram. [Specimen Page, No. 9.] CARBONIC ANHYDRIDE.... | |
 | James Hamblin Smith - 1875 - 280 σελίδες
...does not lie, the difference of the triangle* thus formed is equal to half the parallelogram. Ex. 2. The two triangles, formed by drawing straight lines...point within a parallelogram to the extremities of its opposite sides, are together half of the parallelogram. CARBONIC ANHYDRIDE. 33 (sometimes carbonic... | |
 | Roland Knyvet Wilson - 1875 - 402 σελίδες
...difference of the triangles thus formed is equal to half the parallelogram. Ex. 2. The two trinngles, formed by drawing straight lines from any point within a parallelogram to the extremities of its opposite sides, are together half of the parallelogram. [J. HAMBLIN SMITH'S GEOMETRY— -See Page... | |
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If from a point, without a parallelogram, there be drawn two straight lines to the extremities of the two opposite sides, between which, when produced, the point does not lie, the difference of the triangles thus formed is equal to half the parallelogram.... 
