 | Nathan Daboll - 1839 - 220 σελίδες
...cube of the last quotient figure under these two products, and call their amount the subtrahend. VIII. Subtract the subtrahend from the dividend, and to the remainder bring down the next period for a new dividend, with which proceed as before ; and so on till the whole is finished. Note 1. If the subtrahend... | |
 | Benjamin Greenleaf - 1858 - 472 σελίδες
...for a true divisor. Multiply the true divisor by the last figure of the root; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. Multiply the square of (lie root figures already found by 3, and to the product annex... | |
 | Benjamin Greenleaf - 1858 - 458 σελίδες
...for a true divisor. Multiply the true divisor by the last figure of the root : subtract the product from the dividend, and to the remainder bring down the next period far a new dividend. To the last true divisor and the number immediately over it, add the square of... | |
 | Benjamin Greenleaf - 1858 - 456 σελίδες
...period, and trrite its root as the jirst figure of the required root. From that period subtract the cube, and to the remainder bring down the next period for a dividend. Multiply the, square of the root figure by 3, and to the product annex tiro ciphers for a trial diviior,... | |
 | Horatio Nelson Robinson - 1859 - 352 σελίδες
...the complete divisor. V. Multiply the complete divisor by the trial figure, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. VI. Add the square of the last figure of the root, the last term in column II, and the... | |
 | Horatio Nelson Robinson - 1860 - 444 σελίδες
...the complete divisor. V. Multiply the complete divisor by the trial figure ; subtract the. product from the dividend, and to the remainder bring down the next period for a new dividend. VI. Add the square of the last figure of the root, the last term in column II, and the... | |
 | James Bates Thomson - 1860 - 440 σελίδες
...; multiply- the divisor thus completed by the figure last placed in the root ; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. IV. Double the root already found for a new partial divisor, divide, <£c., as before,... | |
 | Daniel Adams - 1861 - 452 σελίδες
...obtained, together with the cube of the last quotient, to the former product for a subtrahend. VII. Subtract the subtrahend from the dividend, and to the remainder bring down the next period for a new dividend, with which proceed as before, till the work is finished. If it happens that the divisor... | |
 | Charles Davies - 1861 - 322 σελίδες
...divisor. IV. Multiply the divisor, thus augmented, by the lastfyurt of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. But if any of the products should be greater than the dividend, diminish the last figure... | |
 | Charles Davies - 1861 - 496 σελίδες
...divisor : IV. Multiply the divixor thus increased, by the last figure of the root j subtract the product from the dividend, and to the remainder bring down the next period for a new dividend: V. Double the whole root thus found, for a new trial divisor, -and continue the operation... | |
| |
Multiply the divisor, thus augmented, by the last figure of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. 
