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Βιβλία Βιβλία 21 - 30 από 44 για Prom' the very process of dividing each of the parts, that is, of increasing the....
" Prom' the very process of dividing each of the parts, that is, of increasing the denominators by multiplying them, it follows, that each denominator must be & factor of the common denominator ; now, multiplying all the denominators together will evidently... "
Adams's New Arithmetic: Arithmetic, in which the Principles of Operating by ... - Σελίδα 95
των Daniel Adams - 1810 - 180 σελίδες
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Adam's New Arithmetic: Arithmetic, in which the Principles of Operating by ...

Daniel Adams - 1833 - 264 σελίδες
...15ths. The $ will become j-%, aad the f will become -^ ; then, -^ taken from -ft leaves t TT 6O. From -the Very process of dividing each of the parts, that...multiplying them, it follows, that each denominator must be A factor of the common denominator ; now, multiplying all the denominators together will evidently...

The Common School Arithmetic: Prepared for the Use of Academies and Common ...

Charles Davies - 1833 - 270 σελίδες
...fraction. Ans. i£t=102|. 6. Beduce 5 of ^ of 4 of 6 to a simple fraction. Ans. ff=2f CASE vi. 4 130. To reduce fractions of different denominators to equivalent fractions having a common denominator. Rt'LE. I. Reduce compound fractions to simple ones, and whole or mixed numbers to improper fraction*....

A system of arithmetic, with the principles of logarithms

Richard Frederick Clarke (the elder.) - 1833
...and 45. Answer, 90 35. Required the least common multiple of 12, 6, 9, and 8. Answer, 72. CASE 7th. To reduce fractions of different denominators to equivalent fractions having a common denominator. Example. Reduce g, |, and J to fractions having a common denominator. 2X8X9=144) 5X3X9=135 V New numerators....

A New Introduction to the Science of Algebra...

Silas Totten - 1836 - 304 σελίδες
...numerator, or multiplying the denominator by this quantity. Thus, 3* - #' 3v 2# 2x .a3 a a3 ab — b2' To reduce fractions of different denominators to equivalent fractions having a common denominator. RULE. (25.) Multiply all the denominators together for a common denominator, and each numerator into all...

A New Introduction to the Science of Algebra...

1836 - 304 σελίδες
...performed either by dividing the numerator, or multiplying the denominator by this quantity. Thus, 7^ reduce fractions of different denominators to equivalent fractions having a common denominator. RULE. (25.) Multiply all the denominators together for a common denominator, and each numerator into all...

Cobb's Explantory Arithmetick, Number Two: Containing the Compound Rules ...

Lyman Cobb - 1836 - 216 σελίδες
...36018* 4. Reduce 4- of 44- of 4-4- to a simple fraction. Ans. -- 01-6Z3 - 1500 RULE. Q. How do you reduce fractions of different denominators to equivalent fractions having a common denominator ? A. Each numerator must be multiplied by all the denominators, except its own, for the new numerator;...

Adams's New Arithmetic: Arithmetic, in which the Principles of Operating by ...

Daniel Adams - 1838 - 262 σελίδες
...is, of increasing the denominators by multiplying them, it follows, that each denominator must be a factor of the common denominator ; now, multiplying...denominators to equivalent fractions, having a common denotninator, — RULE : Multiply together all the denominators for a common denominator, and, as by...

Mental and Practical Arithmetic: Designed for the Use of Academies and Schools

Charles Davies - 1838 - 288 σελίδες
...simple fraction. Ans. f= 7. Reduce 64- of 74- of 6|4 to a simple fraction. . " Ans. CASE VI. § 94. To reduce fractions of different denominators to equivalent fractions having a common denominator. RULE. I. Reduce compound fractions to simple ones, and whole or mixed numbers to improper fractions. II....

Arithmetic, in which the Principles of Operating by Numbers are Analytically ...

Daniel Adams - 1839 - 264 σελίδες
...The § will become ^f, and the £ will become ^ ; then, ^ taken from ±% leaves TV, Ans. IT 6O. From the very process of dividing each of the parts, that...multiplying them, it follows, that each denominator must be a. factor of the common denominator ; now, multiplying all the denominators together will evidently...

Adams's New Arithmetic: Arithmetic, in which the Principles of Operating by ...

Daniel Adams - 1840 - 264 σελίδες
...will become •ff , and the f will become -^ ; then, ^ taken from ±% leaves T*s, Ans. 1T 6O. From the very process of dividing each of the parts, that...multiplying them, it follows, that each denominator must be a factor of the common denominator ; now, multiplying all the denominators together will evidently...




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