 | Indiana. State Board of Education - 1886 - 360 σελίδες
...square of 25. By analyzing the foregoing we find that 625, when compared with its square root, contains the square of the tens, plus twice the product of...the tens by the units, plus the square of the units. Q 2 = 81 From the squares in the margin we may 99 3 = 9801 infer that the square of any number con125... | |
 | Andrew Jackson Rickoff - 1886 - 688 σελίδες
...to see where we may find them in the product. Thus, In this case we see that 365. The square of 43 is equal to the square of the tens, plus twice the...the tens by the units, plus the square of the units. v- Q It may be shown that the same is true of any number. Raise the following numbers to the second... | |
 | Christian Brothers - 1888 - 484 σελίδες
...letters, we get the result <* + 2<w + it8. Hence, The square of a number expressed by two figures, equals the square of the tens, plus twice the product of the tens into the units, plus the square of the units. In like manner find the square of each of the following... | |
 | Andrew Jackson Rickoff - 1888 - 464 σελίδες
...to see where we may find them in the product. Thus, in this case we see that 365. The square of 43 is equal to the square of the tens, plus twice the...the tens by the units, plus the square of the units. It may be shown that the same is true of any number. Raise the following numbers to the second power,... | |
 | Charles Scott Venable - 1888 - 402 σελίδες
...cube root may require three places in the third power. III. The square of a number containing tens is equal to the square of the tens plus twice the...the tens by the units plus the square of the units. IV. The cube of a number containing tens and units equals the cube of the tens plus three times the... | |
 | Charles Austin Hobbs - 1889 - 362 σελίδες
...329= 40x7 + 72 1880 = 402 + 40 x 7 472 = 2209 = 402 + 2 x (40 x 7) + 7* In general, the square of any number composed of tens and units is equal to the...the tens by the units, plus the square of the units. I. Find the square root of 5329. 5329(70 + 3 = 73 Since the number consists 4900 of two periods, the... | |
 | Charles Davies - 1889 - 330 σελίδες
...x2 + Ixy + y2 = x2 + (2x + y)y. That is, the number is equal to the square of the tens in its root, plus twice the product of the tens by the units, plus the square of the units. We first find the tens of the root. Since the square of tens can contain no significant figure less... | |
 | Charles Austin Hobbs - 1889 - 370 σελίδες
...143)429 from 5329, the remainder is 429 429. Since the square of the tens has been subtracted, 429 equals twice the product of the tens by the units plus the square of the units ; this is the same as twice the tens plus the units multiplied by the units. Thus the two factors of... | |
 | John Bernard Clarke - 1889 - 566 σελίδες
...from the remainder that part of the square of the tens plus the units not already subtracted, viz., twice the product of the tens by the units, plus the square of the units, on the principle indicated in (218). We thus have the following RULE.—Separate the given number into... | |
 | James William Nicholson - 1889 - 408 σελίδες
...t, and the units by M, we have the Formula: (< + «)2 = <2 + 2<« + U* . That is, the square of any number composed of tens and units is equal to the square of the tens, -(- twice the product of the tens by the units, -\- the square of the units. 34 = 34 = 30 + 4 : 30... | |
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The square of a number composed of tens and units is equal to the square of the tens, plus twice the product of the tens by the units, plus the square of the units. tens? 
