 | George Augustus Walton - 1864 - 376 σελίδες
...square of the last. Multiply this sum by the last term, and subtract the product from the dividend. To the remainder bring down the next period for a new dividend. Multiply the square of the terms of the root already found (considered as fens), by three for a trial... | |
 | George Augustus Walton - 1864 - 364 σελίδες
...true divisor thus obtained by the last term of the root, and subtract this product from the dividend ; to the remainder bring down the next period for a new dividend. Double the terms of the root already found for a new trial divisor, and proceed as before. NOTE I.... | |
 | Horatio Nelson Robinson - 1864 - 444 σελίδες
...result will be the complete divisor. V. Multiply the complete divisor by the last figure of the root, subtract the product from the dividend, and to the remainder bring down another period for a, new dividend. VI. Add together the last complete divisor, the last correction,... | |
 | Charles Davies - 1865 - 372 σελίδες
...also annex it to the divisor. IV. Multiply the divisor thus increased, by the last JigKt of the root ; subtract the product from the dividend, and to the remainder bring down the next period for a neic dividend. V. Double the whole root thus found, for a new trial divisor, and continue the operation... | |
 | W H. Wingate - 1865 - 150 σελίδες
...trial divisor and the last figure in the root — add these three results for a subtrahend which take from the dividend, and to the remainder bring down the next period, and proceed as before. EXAMPLE. — Find the cube root of 4.410944. 4.410944(164 1гхЗ=3 Trial Divisor... | |
 | Joseph Ray - 1866 - 250 σελίδες
...the right of the divisor. 4. Multiply the divisor, thus increased, by the last figure of the root; subtract the product from the dividend, and to the...remainder bring down the next period for a new dividend. 5. Double the whole root already found for a new divisor, and continue the operation as before, until... | |
 | Joseph Ray - 1866 - 420 σελίδες
...the right of the divisor. 4th. Multiply the divisor thus increased by the last figure of the root; subtract the product from the dividend, and to the...remainder bring down the next period for a new dividend. 5th. Double the whole root already found for a new divisor, and continue the operation as before, until... | |
 | Joseph Ray - 1852 - 422 σελίδες
...of the divisor. 4th. Multiply the divisor thus increased by the last figure of the root, sulitract the product from the dividend, and to the remainder bring down the -next period for a new dividend. f>th. Double the whole root already found for a new divisor, and ccn- ^ tinue the operation as before,... | |
 | Robert Thomson (of Southampton.) - 1866 - 180 σελίδες
...unit's place of the divisor. Fifth. — Multiply this divisor by the last figure in the quotient, and subtract the product from the dividend, and to the remainder bring down the next point for a new dividend, double the last figure set in the divisor and proceed as before to the last... | |
 | Joseph Ray - 1866 - 252 σελίδες
...Multiply the divisor, thus increased, by the last figure of the root; subtract the product from tJic dividend, and to the remainder bring down the next period for a new dividend. 5. Double the whole root already found for a new divisor, and continue the operation as before, until... | |
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Multiply the divisor, thus augmented, by the last figure of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. 
