 | Benjamin Greenleaf - 1858 - 458 σελίδες
...and add it to the same for a true divisor. Multiply the true divisor by the last figure of the root : subtract the product from the dividend, and to the remainder bring down the next period far a new dividend. To the last true divisor and the number immediately over it, add the square of... | |
 | Charles Haynes Haswell - 1858 - 350 σελίδες
...period, and place its root in the quotient ; subtract the square number from the left-hand period, and to the remainder bring down the 'next period for a new dividend. Double the root already found for a divisor ; find how many times this incomplete divisor is contained... | |
 | Benjamin Greenleaf - 1858 - 332 σελίδες
...represent? What is the rule for extracting the cube root ? Subtract the subtrahend from the dicidend, and to the remainder bring down the next period for a new dicidend, with which proceed at before; and so on, till the whole is completed. NOTE 1. — In separating... | |
 | Horatio Nelson Robinson - 1859 - 362 σελίδες
...the result will be the complete divisor. V. Multiply the complete divisor by the trial figure, and subtract the product from the dividend, and to the...remainder bring down the next period for a new dividend. VI. Add the square of the last figure of the root, the last term in column II, and the complete divisor... | |
 | Charles Guilford Burnham - 1859 - 338 σελίδες
...write the cube of the last quotient figure, and call their sum the subtrahend. Subtract the subtrahend from the dividend, and to the remainder bring down the next period, for a new dividend, and proceed as before, till the work is finished. EXAMPLES. 2. What is the cube root of 1906624 ? , Operation.... | |
 | Horatio Nelson Robinson - 1860 - 444 σελίδες
...divisor, and the result will be the complete divisor. V. Multiply the complete divisor by the trial figure ; subtract the. product from the dividend,...remainder bring down the next period for a new dividend. VI. Add the square of the last figure of the root, the last term in column II, and the complete divisor... | |
 | James Bates Thomson - 1860 - 440 σελίδες
...the partial divisor ; multiply- the divisor thus completed by the figure last placed in the root ; subtract the product from the dividend, and to the...remainder bring down the next period for a new dividend. IV. Double the root already found for a new partial divisor, divide, <£c., as before, and thus continue... | |
 | Popular educator - 1860 - 536 σελίδες
...dividend by the first term of the divisor. Multiply the whole divisor by the term placed in the quotient ; subtract the product from the dividend ; and to the remainder bring down as many of the following terms as shall be necessary to continue the operation. Divide again by the... | |
 | Benjamin Greenleaf - 1860 - 456 σελίδες
...the true divisor, which multiply by the last root figure and subtract the product from the dividend. To the remainder bring down the next period for a new dividend. Double the root already found for a new trial divisor, and continue the operation as before, till all... | |
 | Charles Davies - 1861 - 496 σελίδες
...annex it to the divisor : IV. Multiply the divixor thus increased, by the last figure of the root j subtract the product from the dividend, and to the...remainder bring down the next period for a new dividend: V. Double the whole root thus found, for a new trial divisor, -and continue the operation as before,... | |
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Multiply the divisor, thus augmented, by the last figure of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. 
