 | 1899 - 824 σελίδες
...assumed without proof. Among the other error» in proving the second part it wa.s taken for true that the area of a parallelogram is equal to the product of its two adjacent sides. Questions 7. 8, and 9 were correctly demonstrated by nearly all (a considerable... | |
 | 1901 - 548 σελίδες
...inches; that is, a figure 2 inches square, and its area is 4 square inches. 25. Area of a Parallelogram. The area of a parallelogram is equal to the product of its base and altitude. Let AB CD, Fig. 4, be any parallelogram. Draw A Fand BE perpendicular to the two opposite sides AB and... | |
 | Thomas Franklin Holgate - 1901 - 462 σελίδες
...contains as many squares as is represented by the product of its base and altitude. 305. COROLLARY I. The area of a parallelogram is equal to the product of its base and altitude. For, any parallelogram is equal in area to a rectangle having the same base and an equal altitude.... | |
 | Alan Sanders - 1901 - 260 σελίδες
...units) in the rectangle is 4 x 3 or 12. The area then is 12 square feet. 588. COROLLARY. The area of any parallelogram is equal to the product of its base and altitude. Let ABCD be any parallelogram f BEC and DE be its altitude. To Prove ABCD = AD x DE. Proof. Draw AF _L to AD, meeting... | |
 | Arthur Schultze - 1901 - 260 σελίδες
...754. A rectangular field is 24 yds. long and 15 yds. wide. Find the area. PROPOSITION IV. THEOREM 341. The area of a parallelogram is equal to the product of its base and its altitude. E Hyp. ABCD is a parallelogram, having the base AB = b, and the altitude BE = h. To prove... | |
 | Thomas Franklin Holgate - 1901 - 462 σελίδες
...303. (6) The area of any rectangle is equal to the product of its base and its altitude. § 304. (7) The area of a parallelogram is equal to the product of its base and its altitude. § 305. (8) The area of a square is equal to the square of any one of its sides. § 307.... | |
 | Arthur Schultze - 1901 - 392 σελίδες
...field is 24 yds. long and 15 yds. wide. Find the area. PLANE GEOMETRY PROPOSITION IV. THEOREM 341. The area of a parallelogram is equal to the product of its base and its altitude. F E G Hyp. ABCD is a parallelogram, having the base AB = b, and the altitude BE = h.... | |
 | Arthur Schultze, Frank Louis Sevenoak - 1901 - 396 σελίδες
...rectangle is 360 square inches, and its base ia 4 yds. Find the altitude. PROPOSITION IV. THEOREM 341. TJie area of a parallelogram is equal to the product of its base and its altitude. Hyp. ABCD is a parallelogram, having the base AB — b, and the altitude BE = h. To prove... | |
 | Arthur Schultze - 1901 - 260 σελίδες
...rectangular field is 24 yds. long and 15 yds. wide. Find the area. PROPOSITION IV. THEOREM 341. TTie area of a parallelogram is equal to the product of its base and its altitude. A Hyp. ABCD is a parallelogram, having the base AB = b, and the altitude BE = h. To frnn.e... | |
 | Arthur Schultze, Frank Louis Sevenoak - 1901 - 394 σελίδες
...field is 24 yds. long and 15 yds. wide. Find the area. PLANE GEOMETRY PROPOSITION IV. THEOREM 341. The area of a parallelogram is equal to the product of its base by its altitude. E Hyp. ABCD is a parallelogram, having the base AB = b, and the altitude BE =... | |
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The area of a parallelogram is equal to the product of its base and its height: A = bx h. 
