 | Benjamin Greenleaf - 1844 - 208 σελίδες
...for the first figure of the root, and the square number under the period, and subtract it therefrom, and to the remainder bring down the next period for a dividend. 3. Place the double of the root already found, on the left hand of the dividend for a divisor. 4. Seek... | |
 | 1845 - 210 σελίδες
...contained in the left hand period, and set its root on the right of the given number: subtract said square from the left hand period, and to the remainder bring down the next period for a dividual. 3. Double the root for a divisor, and try how often this divisor (with the figure used in... | |
 | 1845 - 196 σελίδες
...root. 2. Find the first figure of the root by the table of powers, or by trial ; subtract its power from the left hand period, and to the remainder bring down the first! figure in the next period for a dividend. 3. Involve the root to the next inferior power to... | |
 | Horatio Nelson Robinson - 1845 - 310 σελίδες
...power. 2.' Find the first figure of the root by the table of powers, or by trial; subtract its power from the left hand period, and to the remainder bring down the first figure in the next period for a dividend. 3. Involve the root to the next inferior power to that... | |
 | Dana Pond Colburn - 1855 - 396 σελίδες
...place its root as the highest denomination of the required root. Third. Subtract the square thus found from the left hand period, and to the remainder bring down the next period, calling the result a dividend. Fourth. Double the part of the root already found for a trial divisor.... | |
 | Charles Davies, William Guy Peck - 1855 - 628 σελίδες
...and place its cube root on the right, after the manner of a quotient in division. Subtract this cube from the left hand period, and to the remainder bring down the first figure of the next period and call this number the dividend. Take three times the square of the... | |
 | Benjamin Peirce - 1855 - 308 σελίδες
...and its root is the left hand figure of the required root. Subtract the square of the root thus found from the left hand period, and to the remainder bring down the second period "for a dividend. Double the root for a divisor, and the quotient of the dividend exclusive... | |
 | Dana Pond Colburn - 1856 - 392 σελίδες
...hand period, and place its root as the first figure of the required root. Third. Subtract this cube from the left hand period, and to the remainder bring down the next period, calling the result a dividend. Fourth. Find three times the square of the part of the root already... | |
 | Roswell Chamberlain Smith - 1856 - 334 σελίδες
...last period on the left, write its root on the right, as a quotient, subtract the square from the said period, and to the remainder bring down the next period for a dividend. 16. Double the root (quotient) for a partial divisor, and on its right, place, for the total divisor,... | |
 | Charles Guilford Burnham - 1857 - 328 σελίδες
...the left-hand period, and place its root as a quotient in division. III. Subtract the cube from said period, and to the remainder bring down the next period, for a dividend. IV. Multiply the square of the quotient by 300, calling it the triple square, and the, quotient by... | |
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Subtract the square number from the left hand period, and to the remainder bring down the next period for a dividend. III. Double the root already found for a divisor ; seek how many times the divisor is contained in the dividend... 
