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" Multiply the last term by the ratio, from the product subtract the first term, and divide the remainder by the ratio, less 1; the quotient will be the sum of the series required. "
Practical and Mental Arithmetic ... - Σελίδα 263
των Roswell Chamberlain Smith - 1839
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The New Federal Calculator, Or Scholar's Assistant: Containing the Most ...

Thomas Tucker Smiley - 1868
...that product will be the last term. 3. Multiply the last term by the ratio; from the product fcubtract the first term, and divide the remainder by the ratio, less 1, for the sum of the series. Question». What is Geometrical Progression? What № the ratio ? By what...

Common School Arithmetic: Combining the Elements of the Science with Their ...

John Homer French - 1869 - 335 σελίδες
...quotient is 1. The number of divisions will be the number of terms. V. To find the sum of the series. Multiply the last term by the ratio, from the product...term, and divide the remainder by the ratio less 1. fit OELEMS. 6. The first term of an ascending geometrical series is 7, and the ratio is 3. What is...

New Elementary Algebra

Horatio Nelson Robinson - 1874 - 312 σελίδες
...1)S = rL — a. Or, B = T=r (*) Hence, the following RULE. Multiply the last term by the ratio, and from the product subtract the first term, and divide the remainder by the ratio less one. EXAMPLES FOR PRACTICE. 1. The first term is 5, the last term 1280, and the ratio 4 ; what is the...

A Practical Business Arithmetic ...

Lorenzo Fairbanks - 1875
...to a power whose index is equal to the number of terms, and multiply this power by the first term ; from the product subtract the first term, and divide the remainder by the ratio less 1. NOTE. — This rule is employed in computing the values of annuities. EXAMPLES. 1. The first term of...

Eaton's Elementary Algebra, Designed for the Use of High Schools and Academies

William Frothingham Bradbury - 1875
...rS=ar+ar,-\- ar* + _|-i_|-ir (2) Subtracting (1) from (2), r S — A = Ir — a Whence, S = . Hence, RULE. Multiply the last term by the ratio, from the product subtract tlw first term, and divide the remainder by the ratio less one. 1. Given a = 2, I = 20000, and r= 10,...

The Standard Arithmetic: For Schools of All Grades and for Business ..., Τόμος 2

James E. Ryan - 1877
...equals be divided by (r — 1), s will stand 7j« ft equal to (lr— a)-f-(r— l),or, as above, s= .-. RULE. — Multiply the last term by the ratio, from...term, and divide the remainder by the ratio less 1 . EXERCISE CXLIV. 1,2. How many ancestors hast thou, reckoning 20 generations back ; and how many of...

Bradbury's Elementary Algebra: Designed for the Use of High Schools and ...

William Frothingham Bradbury - 1877 - 269 σελίδες
...г, rS=ar+ari + ar, + -\-l-\-lr (¥) Subtracting (1) from (2), r S — S=lr — a Whence, S= . Hence, RULE. Multiply the last term by the ratio, from the product subtract the ßrst term, and divide the remainder by tlie ratio less one. 1. Given a = 2, I = 20000, and r — 10,...

New Practical Algebra: Adapted to the Improved Methods of Instruction in ...

James Bates Thomson - 1878 - 312 σελίδες
...last term in the given series. Substituting ¡r for ar", we have FOKMULA II. s = — — • r— i RULE. — Multiply the last term by the ratio, from...first term, and divide the remainder by the ratio less one. fW For the method of finding the sum of an infinite descending series, see Art. 435. 1. Given...

Bradbury's Eaton's Practical Arithmetic ...

William Frothingham Bradbury - 1882 - 374 σελίδες
...one fourth of this remainder must be the sum of the given series ; but 4 is the ratio less 1. Hence, Rule. Multiply the last term by the ratio, from the...first term, and divide the remainder by the ratio less one. 106. The extremes are 4 and 2916, and the ratio 3 ; what is the sum of the series? Ans. 4372....

Bradbury's Eaton's Practical Arithmetic ...

William Frothingham Bradbury - 1879
...fourth of this remainder must be the sum of the given series ; but 4 is the ratio less 1. Hence, Bule. Multiply the last term by the ratio, from the product...first term, and divide the remainder by the ratio less one. 106. The extremes are 4 and 2916, and the ratio 3 ; what is the sum of the series 1 Ans. 4372....




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