 | Euclid - 1835 - 540 σελίδες
...the rectangle CB, BD, that is, the square of AC alone is less-p. than the squares of CB, BA, by_fc> twice the rectangle CB, BD. Secondly, Let AD fall...triangle ABC: Then, because the angle at D is a right A angle, the angle A CB is greater d than a right angle ; and therefore the square of AB is equal ;... | |
 | John Playfair - 1835 - 336 σελίδες
...= AC2 (37. 1.) ; therefore BC' -f AB2=2BC.BD -f AC2 ; that is, AC2 is less than BC2-fAB2 by 2BC.BD. BD Secondly, Let AD fall without the triangle ABC ;* Then because the ani^le at D is a right angle, the angle ACS is greater (9. 1.) than a right angle, and AB2 = (11. 2.)... | |
 | John Playfair - 1836 - 148 σελίδες
...AC, and twice the rectangle CB, BD, that is, the square of AC alone is less than the squares of CB, BA by twice the rectangle CB, BD. Secondly, Let AD...angle at D is a right angle, the angle ACB is greater (5. 2.) than a right angle ; and therefore the square of AB is equal (26. 2.) to the squares of AC,... | |
 | John Playfair - 1836 - 488 σελίδες
...AC2 c ; therefore BC2 + AB2 ij=2 BC.BD + AC2; that is, •» AC2 is less than BC2 + AB2 by 2BC.BD. Secondly, Let AD fall without the triangle ABC * :...the angle at D is a right angle, the angle ACB is greater"1 than a right angle, and AB2 — e AC2 d 16. 1. + BC2 + 2BC.CD. Add BC2 to each ; thenAB2... | |
 | Andrew Bell - 1837 - 290 σελίδες
...; that is, the square of AC alone is less than the squares of CB, BA, by twice the rectangle CB-BD. Secondly, let AD fall without the triangle ABC ; then,...angle, the angle ACB is greater than a right angle (1. 16) ; and therefore the square of AB is equal to the squares of AC, CB, and twice the rectangle... | |
 | John Playfair - 1837 - 332 σελίδες
...DA2=AC2 (47. 1.) ; therefore BC2+AB2 = 2BC.BD + AC2 ; that is, AC2 is less than BC2+AB2 by 2BC.BD. B nc Secondly, let AD fall without the triangle ABC :*...angle at D is a right angle, the angle ACB is greater (16. 1.) than a right angle, and AB2= (12. 2.) AC2+BC2+2BC.CD. Add BC2 to each; then AB2+BC'=AC2-|-2BC2+2BC.CD.... | |
 | Robert Simson - 1838 - 434 σελίδες
...that is, the square of AC alone is less than the squares of CB, BA, by twice the rectangle CB, BB. A Secondly, let AD fall without the triangle ABC : then,...angle at D is a right angle, the angle ACB is greater (16. 1.) than a right angle; and therefore the square of AB is equal (12. 2.) to the squares of AC,... | |
 | Euclides - 1838 - 264 σελίδες
...that is, the square of AC alone is less than the squares of CB, BA, by twice the rectangle CB-BD. , Secondly, let AD fall without the triangle ABC: then,...the angle at D is a right angle, the angle ACB is »j6 1 greater* than a right angle ; and therefore the square of AB ia *It. S. equal* to the squares... | |
 | Euclides - 1841 - 378 σελίδες
...AC, and twice the rectangle CB, BD; that is, the square of AC alone is less than the squares of CB, BA, by twice the rectangle CB, BD. Secondly, let AD...then, because the angle at D is a right angle, the an* 16. 1. gle ACB is greater* than a right angle; therefore the square of AB * 12. 2. is equal* to... | |
 | John Playfair - 1842 - 332 σελίδες
...DA2=AC2 (47. 1.) ; therefore BC2+AB2= 2BC.BD + AC2 ; that is, AC2 is less than BC2+AB2by2BC.BD. BDC Secondly, let AD fall without the triangle ABC :*...angle at D is a right angle, the angle ACB is greater (16. 1.) than a right angle, and AB2= (12. 2.) AC2+BC2 + 2BC.CD. Add BC2 to each; then AB2+BC2 = A.C2-f2BC2+2BC.CD.... | |
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CB, BA, by twice the rectangle CB, BD. Secondly, Let AD fall without the triangle ABC. Then, because the angle at D is a right angle, the angle ACB is greater than a right angle ; (i. 
