 | Daniel Barnard Hagar - 1873 - 278 σελίδες
...root at the right for the first figure of the required root. Subtract this square from the highest period, and to the remainder bring down the next period for a dividend. Divide the dividend, omitting its right-hand order, by twice the root already found, and write the... | |
 | Horatio Nelson Robinson - 1874 - 340 σελίδες
...period, and place its root for the first figure of the required root. Subtract the cube from the first period, and to the remainder bring down the next period for a dividend. III. At the left of the dividend, write three timen the square of the root already found, and annex... | |
 | Horatio Nelson Robinson - 1874 - 490 σελίδες
...and write its root for the first figure in the required root; subtract the cube from the left hand period, and to the remainder bring down the next period for a dividendIll. At the left of the dividend write three times the square of the first figure of the root,... | |
 | Horatio Nelson Robinson - 1875 - 430 σελίδες
...write its root for the first figure, in the root sought ; subtract the square number from the left-hand period, and to the remainder bring down the next period for a dividend. III. At the left of the dividend write twice the first figure of the root, for a trial divisor ; divide... | |
 | Lorenzo Fairbanks - 1875 - 472 σελίδες
...place its root on the right for the first figure of the root ; subtract the cube from the left-hand period, and to the remainder bring down the next period for a dividend. III. Take three times the square of the part of the root already found for a trial divisor. IV. Find... | |
 | William Guy Peck - 1875 - 348 σελίδες
...the required root; subtract this cube from the first period, and to the remainder annex the following period for a dividend. ///. Multiply the square of the root already found by 3, and to the product annex two ciphers for a trial divisor; find how many times this is contained... | |
 | Benjamin Greenleaf - 1876 - 344 σελίδες
...in the left-hand period, and place its root on the right. Subtract the cube, thus found, from this period, and to the remainder bring down the next period...square of the root already found by 300 for a divisor, by which divide the dividend, and place the quotient, usually diminished by one or two units, for the... | |
 | George Augustus Walton - 1876 - 358 σελίδες
...period, and write its root as the first term in the answer. Subtract the square number from the left hand period, and to the remainder bring down the next period for a dividend. Take twice the root already found for a trial divisor ; rejecting the right hand figure of the dividend,... | |
 | Joseph Ray - 1877 - 402 σελίδες
...period on the left; place its root on the right, like a quotient in division; subtract the cube from the period, and to the remainder bring down the next period for a dividend. 3. Square the root found, and multiply it by 300 for a trial divisor. Find how many times the trial... | |
 | Benjamin Greenleaf - 1879 - 350 σελίδες
...the left-hand period, and place its root on the right ; subtract the cube of this root from the first period, and to the remainder bring down the next period for a dividend. Take three times the square of the root already fonnd, for a trial divisor ; divide the dividend omitting... | |
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... and to the remainder bring down the next period for a dividend. 3. Place the double of the root already found, on the left hand of the dividend for a divisor. 4. Seek how often the divisor is contained... 
