 | Charles Haynes Haswell - 1844 - 298 σελίδες
...left-hand period, and plnce Its root in the quotient; subtrnct the square number from the left-hand period, and to the remainder bring down the next period for a dividend. Double the root already found for a divisor ; find how many times the divisor is contained in the dividend,... | |
 | Benjamin Greenleaf - 1844 - 208 σελίδες
...for the first figure of the root, and the square number under the period, and subtract it therefrom, and to the remainder bring down the next period for a dividend. 3. Place the double of the root already found, on the left hand of the dividend for a divisor. 4. Seek... | |
 | Benjamin Greenleaf - 1844 - 204 σελίδες
...for the first figure of the root, and the square number under the period, and subtract it therefrom, and to the remainder bring down the next period for a dividend. 3. Place the double of the root already found, on the left hand of the dividend for a divisor. 4. Seek... | |
 | 1845 - 210 σελίδες
...period, and set its root on the right of the given number: subtract said square from the left hand period, and to the remainder bring down the next period for a dividual. 3. Double the root for a divisor, and try how often this divisor (with the figure used in... | |
 | James Bates Thomson - 1846 - 402 σελίδες
...placing its root on the right of the number for the first figure of the root, subtract its cube from the period, and to the remainder bring down the next period for a dividend. III. Square the root already found, giving it its true local value ; multiply this square by 3, and... | |
 | James Bates Thomson - 1846 - 354 σελίδες
...placing its root on the right of the number for the first figure of the root, subtract its cube from the period, and to the remainder bring down the next period for a dividend. III. Square the root already found, giving it its true local value ; multiply this square by 3, and... | |
 | James Bates Thomson - 1846 - 362 σελίδες
...2 on the right of the given number for tke first figure in the root, we subtract its cube from the period, and to the remainder bring down the next period for a dividend. This shows that we have 7625 solid feet to be added to the cubical mound already found. 3. We square... | |
 | Almon Ticknor - 1846 - 276 σελίδες
...place <he root to the right of the given number, and subtract the cube of the root from the left hand period, and to the remainder bring down the next period for a dividend. 3. Square the root, and multiply it by three for a defective divisor. 4. Reserve mentally the units... | |
 | Joseph Ray - 1848 - 250 σελίδες
...the right, after the manner of a quotient in division. Subtract the square of the root from the left period, and to the remainder bring down the next period for a dividend. 3d. Double the root already found, and place it on the left for a divisor. Find how many times the... | |
 | Almon Ticknor - 1849 - 156 σελίδες
...placing its root on the right of the number for the first figure of the root, subtract its cube from the period, and to the remainder bring down the next period for a dividend. 3. Square the root already found, giving it its true local value ; multiply this square by 3, and place... | |
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... and to the remainder bring down the next period for a dividend. 3. Place the double of the root already found, on the left hand of the dividend for a divisor. 4. Seek how often the divisor is contained... 
