 | Stephen Pike - 1824 - 212 σελίδες
...hand period, and set its root on the right of the given number: subtract said cube from the left hand period, and to the remainder bring down the next period for a dividual. 3. Square the root and multiply the square by 3 for a defective divisor. 4. Reserve mentally... | |
 | Nicolas Pike, Dudley Leavitt - 1826 - 214 σελίδες
...for the first figure of the root, and the square number under the period, then subtract it therefrom, and to the remainder bring down the next period for a dividend. 3. Place double of the root, already found, on the left hand of the dividend for a divisor. 4. Seek... | |
 | Nicolas Pike, Dudley Leavitt - 1826 - 222 σελίδες
...for the first figure of the root, and the square number under the period, then subtract it therefrom, and to the remainder bring down the next period for a dividend. 3. Place double of the root, already found, on the left hand of the dividend for a divisor. 4. Seek... | |
 | Zachariah Jess - 1827 - 226 σελίδες
...hand period, which place to the right of the given number, and subtract the cube thereof from said period; and to the remainder bring down the next period for a dividual. j ?,.'•.. Thirdly, Take the triple square of the ascertained root for a defective divisor.... | |
 | William Slocomb - 1828 - 160 σελίδες
...left hand period, and place the root of it in the quotient, and subtract the square itself from the period, and to the remainder bring down the next period for a dividend. ft 3. Place the double of the root, already found, on the left hand of the dividend for a divisor.... | |
 | Daniel Adams - 1828 - 266 σελίδες
...period, and write its root as a quotient in division. Subtract the square number from the left hand period, and to the remainder bring down the next period for a dividend. III. Double the root already found for a divisor ; seek how many times the divisor is contained in... | |
 | Daniel Adams - 1828 - 286 σελίδες
...period, and write its root as a quotient in division. Subtract the square number from the left hand period, and to the remainder bring down the next period for a dividend. III. Double the root already found for a divisor; seekhow many times the divisor is contained in the... | |
 | Daniel Parker - 1828 - 358 σελίδες
...left-hand period, and place its root in the quotient. 3. Subtract the cube thus found from the said period, and to the remainder bring down the next period for a resolvend. 4 Multiply the square of the quotient by 300, calling it the divisor. 5. Seek how often... | |
 | Martin Ruter - 1828 - 180 σελίδες
...in the left hand period, place the root of it in the quotient, subtract the cube from the left hand period, and to the remainder bring down the next period for a resolvend. 3. Square the quotient, and multiply the square by 3 for a defective divisor. 4. Seek how... | |
 | Nathan Daboll - 1829 - 252 σελίδες
...for the first figure of the root, and the square number under the period, and subtract it therefrom, and to the remainder bring down the next period, for a dividend. 3. Place the double of the root, already found, on the ^teft hand of the dividend, for a divisor. 4.... | |
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... and to the remainder bring down the next period for a dividend. 3. Place the double of the root already found, on the left hand of the dividend for a divisor. 4. Seek how often the divisor is contained in the dividend... 
