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Βιβλία Βιβλία 81 - 90 από 149 για Then multiply the second and third terms together, and divide the product by the....
" Then multiply the second and third terms together, and divide the product by the first term: the quotient will be the fourth term, or answer. "
The Practical Miner's Guide: Treatise on Mine Engineering, Comprisinga Set ... - Σελίδα 135
των John Budge - 1858 - 191 σελίδες
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... An Elementary Arithmetic ... Serving as an Introduction to the Higher ...

George Roberts Perkins - 1850 - 347 σελίδες
...written the three terms of the proportion, or, as usually expressed, having stated the question, then multiply the second and third terms together, and divide the product by the first term. NOTE. — Since there is a ratio between the firsthand second terms, they must be reduced to...

THE UNIVERSITY ARITHMETIC, EMBRACING THE SCIENCE OF NUMBERS, AND THEIR ...

CHARLES DAVIES, LL.D - 1850
...of the remaining numbers in the first place, but when it is less place the greater there. IV. Then multiply the second and third terms together, and divide the product by the ßrst term : the quotient will be the fourth term or answer sought, and will be of the same denomination...

THE WESTERN PRATICAL ARITHMETIC

JOHN L. TALBOTT - 1851
...them till they are; and, if the third consist of several denominations, reduce it to the lowest, then Multiply the second and third terms together and divide the product by the FIRST, and the quotient will be the fourth term or answer. NOTE.— The answer will be of the same denomination...

An Epitome of Navigation and Nautical Astronomy, with Improved Lunar Tables ...

Janet Taylor - 1851 - 621 σελίδες
...the first and third terms may be of the same kind, and the second the same am the number required. Multiply the second and third terms together, and divide the product by the first term, then the quotient will be the answer in the same denomination as the second term, observing to...

Encyclopædia Americana: A Popular Dictionary of Arts, Sciences ..., Τόμος 11

Francis Lieber, Edward Wigglesworth, Henry Vethake - 1851
...less, place the greater of these two terms on the left, and the less in the middle ; and in both cases, multiply the second and third terms together, and divide the product by the first term for the answer, which will always be of the same denomination as the third term. — Note 1. If...

The scholar's guide to arithmetic; or, A complete exercise-book

John Bonnycastle - 1851
...necessary, to the same denomination, and the third to the lowest denomination mentioned in it. Then multiply the second and third terms together, and divide the product by the first, and the quotient will be the answer, in the same denomination that the third term was reduced to ;...

The young ladies' guide to practical arithmetic and book-keeping, with forms ...

G. Morrison - 1851
...greater than the third, place the least of the other two terms as the first ; but it' less, the contrary. Multiply the second and third terms together, and divide the product by the first, and the quotient is the answer, and which is always of the same name with that to which the third term...

Encyclopaedia Americana

Francis Lieber - 1851
...less, place the greater of these two terms on the left, and the less in the middle; and in both cases, multiply the second and third terms together, and divide the product by the first term for the answer, which will always be of the same denomination as the third term.—Note I. If...

An Elementary Arithmetic Designed for Academies and Schools: Also Serving as ...

George Roberts Perkins - 1851 - 347 σελίδες
...written the three terms of the proportion, or, as usually expressed, having stated the question, then multiply the second and third terms together, and divide the product by thejlrst term. NOTE.—Since there is a ratio between the first and second terms, they mast be reduced...

A familiar explanation of the elementary rules of arithmetic. (A familiar ...

rev. Frederick Calder - 1852
...and if the third term consist of several denominations, reduce it to the lowest name mentioned. Then multiply the second and third terms together, and divide the product by the first: the quotient will be the answer or fourth term, expressed in the same denomination as that in which...




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