 | Popular educator - 1860 - 536 σελίδες
...dividend by the first term of the divisor. Multiply the whole divisor by the term placed in the quotient ; subtract the product from the dividend ; and to the remainder bring down as many of the following terms as shall be necessary to continue the operation. Divide again by the first term... | |
 | Horatio Nelson Robinson - 1860 - 444 σελίδες
...and the result will be the complete divisor. V. Multiply the complete divisor by the trial figure ; subtract the. product from the dividend, and to the remainder bring down the next period for a new dividend. VI. Add the square of the last figure of the root, the last term... | |
 | James Bates Thomson - 1860 - 440 σελίδες
...the partial divisor ; multiply- the divisor thus completed by the figure last placed in the root ; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. IV. Double the root already found for a new partial divisor, divide,... | |
 | Charles Davies - 1861 - 322 σελίδες
...at the right of the divisor. IV. Multiply the divisor, thus augmented, by the lastfyurt of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. But if any of the products should be greater than the dividend,... | |
 | Charles Davies - 1861 - 496 σελίδες
...annex it to the divisor : IV. Multiply the divixor thus increased, by the last figure of the root j subtract the product from the dividend, and to the remainder bring down the next period for a new dividend: V. Double the whole root thus found, for a new trial divisor, -and... | |
 | John Flint (inspector of schools.) - 1862 - 152 σελίδες
...sura of the three parts will be the complete divisor, which multiply by the last figure of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. Proceed in same way, until all the periods are brought down. EXAMPLE.... | |
 | James Bates Thomson - 1862 - 436 σελίδες
...of the partial divisor ; multiply the divisor thus completed by the figure last placed in the root ; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. IV. Double the root already found for a new partial divisor, divide,... | |
 | Elias Loomis - 1862 - 312 σελίδες
...the root and the divisor. 4. Multiply the divisor, thus increased, by the last figure of the root ; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. If the product should be greater than the dividend, diminish the... | |
 | Horatio Nelson Robinson - 1863 - 432 σελίδες
...trial divisor for a complete divisor ; multiply the complete divisor Ъу the trial figure in the root, subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. V. Take the last complete divisor, doubling its right-hand figure,... | |
 | Charles Davies - 1863 - 346 σελίδες
...annex it to the divisor: IV. Multiply the divisor thus increased, by the last figure of the root ; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend : NOTES. — 1. The left-hand period may contain but one figure... | |
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Multiply the divisor, thus augmented, by the last figure of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. 
