 | Charles Davies - 1848 - 302 σελίδες
...and (a+4)2=(64)2; or Which proves that the square of a number composed of tens and units, contains the square of the tens plus twice the product of the tens by the units, plus the square of the units. 94. If, now, we make the units 1, 2, 3, 4, &c, tens, or units of the second order, by annexing to each... | |
 | Pliny Earle Chase - 1848 - 244 σελίδες
...the 7 in the root, and also at the right of the divisor, we multiply by 7, and obtain 469, which is twice the product of the tens by the units plus the square of the units. Hence we deduce the following RULE. *• Separate the number into periods of two figures each, by placing... | |
 | Charles Davies - 1848 - 372 σελίδες
...rectangles FE and EC, and the square ED. Hence, 30 The square of two figures is equal to the square of ths tens, plus twice the product of the tens by the units, plus tht square of the units. Let it now be required to extract the square root of 1296. Since the number... | |
 | Charles Davies - 1850 - 412 σελίδες
...of the square AE, the two rectangles FE and EC, and the square ED. Hence, The square of two figures is equal to the square of the tens, plus twice the...the tens by the units, plus the square of the units. Let it now be required to extract the square root of 1296. Since the number contains more than two... | |
 | Charles Davies - 1850 - 292 σελίδες
...1 , 0~ to which we bring down the two next figures 84. The result of this operation, 1184, contains twice the product of the tens by the units, plus the square of the units. But since tens multiplied by units cannot give a product, of a less name than tens, it follows that... | |
 | Charles Davies - 1852 - 344 σελίδες
...3x6+3', and the sum is 32+2(3 x 6)+62 : that is, 3 + 6 3 + 6 32+3x6 3'+2(3x6)+6 H The square of a number is equal to the square of the tens, plus twice the...the tens by the units, plus the square of the units. The same may be shown by the figure : Let the line AB re- F 30 IP present the 3 tens or 30, and BC... | |
 | David Henry Cruttenden - 1853 - 330 σελίδες
...square of 45. Thus, 45 = 40+ 5 40+ 5 200 + 25 1600 + 200 Hence, 452 = 1600+400 +25=2025 Ans. That is, the square of the tens, plus twice the product of the tens into the units, plus the square of the units. 16. What is the 4th power of 12 ? Ans. 20,736. 17. Find... | |
 | Elias Loomis - 1855 - 356 σελίδες
...841 " 800+40 + 1. If, then, 841 is the square of a number composed of tens and units, it must contain the square of the tens, plus twice the product of...the tens by the units, plus the square of the units. But these three terms are blended together in 841, and hence the peculiar difficulty in determining... | |
 | Thomas Sherwin - 1855 - 262 σελίδες
...+ 9 = 529. Hence, When a number contains units and tens, its second power contains the second power of the tens, plus twice the product of the tens by the units, plus the second power of the units. Let us now, by a reverse operation, deduce the root from the power. Operation.... | |
 | William Smyth - 1855 - 370 σελίδες
...= 2209. Thus the square of a number, consisting of units and tens, is composed of three parts, viz. the square of the tens, plus twice the product of the tens multiplied by the units, plus the square of the units. Thus in 2209, the square of 47, we have The... | |
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The square of a number composed of tens and units is equal to the square of the tens, plus twice the product of the tens by the units, plus the square of the units. tens? 
