 Multiply the divisor, thus increased, by the last figure of the root; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. 5. Double the whole root already found for a new divisor, and continue the...  Putnam's Arithmetic - Σελίδα 196των Rufus Putnam - 1849 - 264 σελίδεςΠλήρης προβολή - Σχετικά με αυτό το βιβλίο
 | Dana Pond Colburn - 1858 - 288 σελίδες
...7th. Multiply the true divisor by the last root figure, placing the product under the dividend. 8th. Subtract the product from the dividend, and to the...remainder annex the next period for a new dividend. 9th. Add together the square of the last quotient^figure, the last true divisor, and the number standing... | |
 | Benjamin Greenleaf - 1858 - 458 σελίδες
...divisor, and add it to the same for a true divisor. Multiply the true divisor by the last figure of the root : subtract the product from the dividend, and to the remainder bring down the next period far a new dividend. To the last true divisor and the number immediately... | |
 | Elias Loomis - 1858 - 394 σελίδες
...root, and the square of the second figure. 5. Multiply the divisor thus increased by the last figure of the root ; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. 6. Take three hundred times the square of the whole... | |
 | Benjamin Greenleaf - 1858 - 472 σελίδες
...the square of the last figure, for a true divisor. Multiply the true divisor by the last figure of the root; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. Multiply the square of (lie root figures already found... | |
 | James B. Dodd - 1859 - 368 σελίδες
...the other part of the root, and multiplying the result by the last figure. 5. Multiply the completed divisor by the last figure in the root; subtract the product from the dividend ; and to the remainder affix the next period, for a new dividend. 6. Find the next incomplete divisor by adding to the last... | |
 | James B. Dodd - 1859 - 368 σελίδες
...the other part of the root, and multiplying the result by the last figure. 5. Multiply the completed divisor by the last figure in the root ; subtract...the product from the dividend ; and to the remainder affix the next period for a new dividend. 6. Find the next incomplete divisor by adding to the last... | |
 | Dana Pond Colburn - 1860 - 388 σελίδες
...Multiply tlie true divisor by the last root figure, placing the product under the dividend. Eighth. Subtract the product from the dividend, and to the...remainder annex the next period for a new dividend. Ninth. Add the square of the last quotient figure to the last true divisor and the number standing... | |
 | Horatio Nelson Robinson - 1860 - 444 σελίδες
...the root to the trial divisor for a complete divisor ; multiply tlie complete divisor by the trial figure in the root, subtract the product from the dividend, and to the remainder briny down the next period for a new dividend. V Multiply the last figure of the last complete divisor... | |
 | James Bates Thomson - 1860 - 440 σελίδες
...on the right of the partial divisor ; multiply- the divisor thus completed by the figure last placed in the root ; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. IV. Double the root already found for a new partial... | |
 | James Stewart Eaton - 1862 - 320 σελίδες
...divisor, and the SUM will be the TRUE DIVISOR. 5. Multiply the true divisor by the last root figure, subtract the product from the dividend, and to the...remainder annex the next period for a new dividend. 6. Find a new trial divisor, and proceed as before, until all the periods have been employed. NOTE... | |
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